2/5x^+7=17

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Solution for 2/5x^+7=17 equation: 



2/5x^+7=17

We move all terms to the left:

2/5x^+7-(17)=0



Domain of the equation: 5x^!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

2/5x^-10=0

We multiply all the terms by the denominator


-10*5x^+2=0

Wy multiply elements

-50x+2=0

We move all terms containing x to the left, all other terms to the right

-50x=-2

x=-2/-50

x=1/25

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